00:01
Hello students, welcome here in this question there are different parts.
00:03
So the first part, this one is 10th question.
00:06
So reaction is given here.
00:08
We have to produce the product for the given reaction series.
00:14
Diethyl ether is given.
00:19
So what happens here, this one is nothing but the grignod rehazent production.
00:25
So this one will produce 1, 2, 3, 1, 2, 3.
00:32
And here mzb are being produced okay so this is a grignot reagent okay and further on reaction with this one is given here the first one is so like this one is a plus and minus charge will be present it will go and attack here and it will give like this so it will be so o minus n g plus b r and here this one is one two so ethyl group is present here and one two three propile group will become here one two three okay so this is a compound on further h3 o plus it will give you the compound c -o -h is there and here it is a methyl group so one two three and there is an methyl group is there so this is a compound you are produced so we can see one two three four five six carbonsor resenter so three methyl we can say three hexanol 3 -ethyl, 3 -hexanol is a compound here.
02:11
3 -ethyl 3 -hexanol.
02:19
Okay, so this is a compound.
02:21
So option a.
02:24
So next question, the reaction of grygnot reagent with an aldehyde followed by dilute acid use.
02:32
So we know that an aldehyde, so 1 -o -h.
02:37
So on -grygnot reagent, for example, example ch3 and zb r we will take.
02:43
So this one is gives like this so it will go and attack here.
02:50
So r -c -o means dilute acid it will give h -plus and here h2, c -h3 will be attacking here...