00:01
In this question we have been given a compound which is 2 methyl pent 1 e.
00:07
Here we have carbon number 1, 2, 3, 4 and 5.
00:14
Now this compound is reacted with the number of reagents and we have to identify the final product.
00:20
The first set of reaction is with bh3 and thh along with h2o2 and naoh.
00:35
Now, this step of reaction is the hydroboration, oxidation, oxidation, and in this, the anti -marconic of major product is obtained and the reaction takes place as the double bond.
00:56
So, we will get the product here which will be oh, c, c, c, c, and the ch3c.
01:07
Now, in the next step, this very compound in which we have 5 carbon atoms and in oh group, this compound is reacted with firstly cocl whole twice dmso at minus 60 degree selfie and then, secondly it is reacted with e .t3.
01:40
This here is the swan oxidation, swan oxidation of alcohol and it will convert this alcohol into aldehyde...