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Hi there.
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In this question, we are combining pairs of aquaic ionic compounds.
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Therefore, we are looking to see if we have double replacement reactions.
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In a double replacement reaction, you may know these as double displacement.
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The terms mean the same thing.
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But what happens is we have two aquisionic compounds reacting and they exchange ions.
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The positive ion from the first combines with the negative ion from the second.
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So those are the parts of a and y here.
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And then for the other possible product, we get the positive ion from the second compound combining with the negative ion from the first.
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The thing about a double replacement reaction is that in order to have a reaction, one of these new products must be insoluble.
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So we must form an insoluble product.
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In most cases, that is a solid or a precipitate.
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Occasionally, it could be a liquid or a gas.
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But what we're looking for here are precipitates.
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And the way that we determine if we get an insoluble product is by using the solubility rules.
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So you should have either a table or a list of rules to help you determine if you're going to get a precipitate or not here.
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Okay, so let's get started and determine if we get a precipitate in each one of these.
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So the first one, we have ammonium sulfide and iron two nitrate.
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So when these exchange ions, one possible product is ammonium with the nitrate.
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Well, as we look at the solubility rules, we see that nitrates are always soluble.
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So this is soluble.
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Our other possible product is iron 2 sulfide.
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Looking at the solubility rules, we see that most sulfides are insoluble.
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The only sulfides that are soluble is when sulfide is combined with a group of.
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One metal or ammonium.
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Well, iron two is neither of those, so this is insoluble, which means it's forming a precipitate, which is abbreviated as p -pt.
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So we want to click the yes button...