A compound contains 6.87 g iron and 13.1 g chlorine. What is the empirical formula?
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Given: Mass of Fe = 6.87 g Molar mass of Fe = 56 g/mol Moles of Fe = 6.87 g / 56 g/mol = 0.123 moles Mass of Cl = 13.1 g Molar mass of Cl = 35.5 g/mol Moles of Cl = 13.1 g / 35.5 g/mol = 0.369 moles Show more…
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