Question

Compound \( X \) has a molar mass of \( 102.17 \mathrm{~g} \cdot \mathrm{~mol}^{-1} \) and the following composition: \begin{tabular}{|l|c|} \hline element & mass \% \\ \hline carbon & \( 58.77 \% \) \\ \hline hydrogen & \( 13.81 \% \) \\ \hline nitrogen & \( 27.42 \% \) \\ \hline \end{tabular} Write the molecular formula of \( X \). \( \square \) \( \square \)

          Compound \( X \) has a molar mass of \( 102.17 \mathrm{~g} \cdot \mathrm{~mol}^{-1} \) and the following composition:
\begin{tabular}{|l|c|}
\hline element & mass \% \\
\hline carbon & \( 58.77 \% \) \\
\hline hydrogen & \( 13.81 \% \) \\
\hline nitrogen & \( 27.42 \% \) \\
\hline
\end{tabular}

Write the molecular formula of \( X \).
\( \square \)
\( \square \)

Compound X has a molar mass of 102.17 g· mol^-1 and the following composition:

element mass %

carbon 58.77 %

hydrogen 13.81 %

nitrogen 27.42 %

Write the molecular formula of X.
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Added by John D.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Rachel Gore

Step 1

This means you have 58.77 g of carbon, 13.81 g of hydrogen, and 27.42 g of nitrogen. Show more…

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Compound \( X \) has a molar mass of \( 102.17 \mathrm{~g} \cdot \mathrm{~mol}^{-1} \) and the following composition: \begin{tabular}{|l|c|} \hline element & mass \% \\ \hline carbon & \( 58.77 \% \) \\ \hline hydrogen & \( 13.81 \% \) \\ \hline nitrogen & \( 27.42 \% \) \\ \hline \end{tabular} Write the molecular formula of \( X \). \( \square \) \( \square \)