00:01
Okay, so here we have a compound with the molecular formula of c6, h10.
00:07
So a good way to find out what the structure is, is first we want to know how many degrees of unsaturation there are.
00:12
So the way that we do that is we take the number of carbons, which is 6, and multiply it by 2, and add 2.
00:23
And then we subtract the number of hydrogen is present, and then divide this whole thing by 2.
00:28
So 6 times 2 is 12 plus 2 is going to be 14, minus 10, over 2.
00:35
So this is 4 over 2 or 2.
00:40
So we have 2 degrees of unsaturation here, which means we're going to have two double bonds somewhere or a double bond in a ring somewhere.
00:48
So next we can look at what the ir tells us.
00:53
So the ir tells us there's an absorption at around 3 ,300.
00:56
And so this is usually indicative of an alkyne being present.
01:00
And so an alkyne, it's a triple bond between two carbons.
01:05
That also accounts for the 2 degrees...