Compute for the amount of barium chromate (g) produced from the reaction of 2 L of 0.50 M barium chloride solution with an excess of 5.00 mol/L potassium chromate solution. BaCl2(aq) + K2CrO4(aq) --> BaCrO4 + 2 KCl(aq)
Added by Claire M.
Step 1
50 M solution. Given: Volume = 2 L, Molarity = 0.50 M Moles = Molarity x Volume Moles = 0.50 mol/L x 2 L Moles = 1 mol Show more…
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