QUESTION 4 If the SRT of a secondary reactor (aeration tank) is 5 days, and the cell biomass concentration (known as MLVSS: Mixed liquor volatile suspended solids) is 2000 mg/L. Compute the hydraulic detention time (in hrs) of aeration tank. (Given: soluble BOD$_5$ in Influent = 93.2 mg/L, soluble BOD$_5$ in effluent = 10 mg/L, decay rate constant = 0.05 day$^{-1}$, yield coefficient = 0.5)

          QUESTION 4
If the SRT of a secondary reactor (aeration tank) is 5 days, and the cell biomass concentration (known as MLVSS: Mixed
liquor volatile suspended solids) is 2000 mg/L. Compute the hydraulic detention time (in hrs) of aeration tank. (Given: soluble
BOD$_5$ in Influent = 93.2 mg/L, soluble BOD$_5$ in effluent = 10 mg/L, decay rate constant = 0.05 day$^{-1}$, yield coefficient = 0.5)

QUESTION 4
If the SRT of a secondary reactor (aeration tank) is 5 days, and the cell biomass concentration (known as MLVSS: Mixed
liquor volatile suspended solids) is 2000 mg/L. Compute the hydraulic detention time (in hrs) of aeration tank. (Given: soluble
BOD5 in Influent = 93.2 mg/L, soluble BOD5 in effluent = 10 mg/L, decay rate constant = 0.05 day^-1, yield coefficient = 0.5)

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Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Sima Sarker

Step 1

SRT (hours) = SRT (days) * 24 SRT (hours) = 5 days * 24 = 120 hours Show more…

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Compute the hydraulic detention time (in hours) of an aeration tank. QUESTION 4 If the SRT of a secondary reactor (aeration tank) is 5 days and the cell biomass concentration (known as MLVSS: Mixed liquor volatile suspended solids) is 2000 mg/L, compute the hydraulic detention time (in hours) of the aeration tank. (Given: soluble BOD5 in influent = 93.2 mg/L, soluble BOD5 in effluent = 10 mg/L, decay rate constant = 0.05 day-1, yield coefficient = 0.5)