00:01
In this question, given a class and greater than cumulative frequency, class is 0 to 2, 2 to 4 to 6, 6 to 8, 8 to 10, 10 to 12, 12 to 40.
00:16
So, the greater than cumulative frequency is given.
00:21
We have to find the frequency, which is minus corresponding consecutive values, that is 34 minus 27, we get 7.
00:30
Xt is 27 minus 16 we get 11 16 minus 15 that is 1 5 2 2 6 total is 34 then we have to find the mean the equation for finding mean is summation x i f i divided by summation f 5 f i so we have to find the x i values xa is the midpoint midpoint means upper limit plus lower limit by two that is up limit is two plus zero is lower limit two plus zero by two we get one likewise all middle value have to find that is here three here five here seven here nine eleven and thirty and its summation is one hundred and ninety eight so the sorry we have to so we have to find summation xi fi fi is 7335 35 18 22 and 78 its summation is 198 so mean is 198 divided by summation fi is 34 that is we get mean is 5 .82 next we have to find the median.
02:08
So we have to find cumulative frequency.
02:11
Cumulative frequency is add the corresponding frequency that is 7 next is 7 plus 11 that is we get 33 next is 33 plus 1 that is 34 sorry so frequency column is this.
02:35
So add the consecutive frequencies that is 7 7 plus 11 which is 18 18 plus 1 which is 19 next is 24 26 28 and 34 so median class is n by tooth class n by 2 the class n is here 34 34 by 2 means we get 70 17 is corresponding to this class because cumulative frequency 18 here so we take the value of cumulative frequency with this class, that is, our median class is 2 to 4...