Compute the voltage across the capacitor at $t = 2 \mu S$. (with two decimal points) 100 $\Omega$ $t = 0$ $+$ $\nu$ 2 nF 200 $\Omega$ + 4 V 150 $\Omega$
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The time constant of the circuit is given by: $\tau = RC = (200 \Omega + 100 \Omega + 150 \Omega)(2 nF) = 900 \times 10^{-9} s = 900 ns$ Show more…
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