00:01
That's all the given quotient.
00:02
In this quotient the focal length is given where it is f is equals to minus of 20 .4 cm as we have to calculate the value of image at different value of object.
00:17
So, by using the formula of mirror using mirror formula that is 1 by f is equals to 1 by u plus 1 by v as we have to calculate the image.
00:36
So, 1 by v is equals to 1 upon f minus 1 upon u.
00:43
Now for different different value of the object.
00:46
So, for first for object u is equals to for u is equals to minus of 39 .8.
00:55
So, the image formed is 1 upon f equals to 1 upon v equals to 1 upon f minus 1 upon u.
01:02
On substituting the value we get 1 upon minus of 20 .4 minus minus plus 1 upon 39 .8 and taking else in we get minus of 41 .85 cm that is the value of image v.
01:20
So, as image v equals to minus of 41 .85 cm at this image is in front of the mirror in front of mirror.
01:37
Secondly, it's a real image.
01:41
It's a real image at is because of the negative sign and secondly it's a inverted image because it is in the front of the mirror...