00:01
First we need to calculate the molarity of the original concentrated nitric acid.
00:06
If it is 70 % nitric acid, i assume by mass, we have 70 grams nitric acid per 100 grams of solution.
00:17
We can then use the density to convert the grams of solution into milliliters.
00:26
They tell us that 1 .42 grams is one milliliter of the solution.
00:32
Then we can convert the milliliters to liters, recognizing there are a thousand milliliters in one liter.
00:40
Now we have liters in the denominator.
00:42
To get molarity, we need moles in the numerator.
00:47
To convert the 70 grams in the numerator into moles, we simply use the molar mass of hno3, where one mole hno3 is 63 .0128 grams.
01:12
Then we have moles in the numerator...