00:01
We are given that we have to perform a testing for two proportions, that is difference of two proportions.
00:09
So for this we are given the value x1 equals to 129, n1 equals to 244 and x2 equals to 140 and n2 equals to 311.
00:27
Now this test has to be conducted at level of significance a or alpha equals to 0 .05.
00:39
Now we have to define the null and the alternative hypothesis for the given case when it is given that we need to test the claim that proportion p1 is greater than proportion of p2.
00:57
So when we test this, the difference of proportion actually is testing to be greater than 0.
01:03
So for and for null hypothesis we assume no difference of proportion.
01:09
So h0 will be p1 minus p2 equals to 0 since no difference statement is made by a null hypothesis.
01:18
And h1 will be testing the claim that is p1 minus p2 greater than 0.
01:24
Hence this is the null and the alternative hypothesis for the given test.
01:33
Now in the next part we have to test the given hypothesis.
01:40
So for this we will use mini tab procedure.
01:45
In mini tab, enter the go to stat, then select basic statistics denoted as bs, then select 2 .5...