00:01
We are looking at the monty hall problem.
00:03
This is a very famous problem from this game show, where there are three doors.
00:07
And the contestant picks a door.
00:09
Let's call them a, b and c.
00:11
So the contestant picks, say, door a.
00:14
One of these doors has a car behind it, the other two have goats.
00:17
And the presenter says, okay, you've picked a.
00:20
Now i'm going to reveal a goat behind one of the other doors.
00:24
Let's say, okay, there's a goat behind b.
00:27
The car wasn't there.
00:28
And then they say, okay, you've seen b.
00:30
Would you like to switch? what should you do? should you switch or should you stick with your original choice? well, let's have a look at the possibilities here.
00:40
So, if the car is behind a, and you switch, you've lost.
00:46
If the car was behind either of the other two and you switch, you've won.
00:50
So what's the probability the car is behind a? well, a third.
00:56
The probability the car is behind b or c is the other two thirds.
01:01
There's an equal chance for a car is behind a third.
01:02
Behind each of them.
01:04
The probability of winning, given, so this is winning by switching, given the car is a, is zero.
01:14
You lose.
01:15
If the car was planned a, you chose a and then you switch, you've lost.
01:19
The probability of winning by switching, given the car is behind b or c, is one.
01:26
If you switch, you win.
01:30
I could express the probability of winning in general by switching, and the probability of winning by switching and the car was behind a plus the probability of winning by switching and the car is behind b or c because the car is always between either a or something else so this covers every way of possibly playing this game and to get the intersection you just multiply these so zero plus two -thirds which means the probability of winning if you switch is two -thirds so that's the algebraic approach and and this is something that people found very difficult to grasp intuitively.
02:14
A lot of people would say, okay, it's 50 -50.
02:17
There are two doors.
02:19
It doesn't matter.
02:20
But it does matter.
02:22
And an intuitive way of approaching this is imagine that instead of three doors, there are 100 doors.
02:29
99 of them have a goat.
02:31
One has a car.
02:32
You pick a door.
02:33
Okay.
02:33
One in a hundred chance.
02:34
You pick the correct one.
02:36
Imagine the presenter then opens up 98 doors to show goats...