00:01
In this problem, we're looking at the nogl theory.
00:03
We're going to start with diatonic fluorine.
00:06
And remember this is a mean of two chlorine ads.
00:09
So these are neutral.
00:12
And if we think about our electronic configuration, we have one fluorine.
00:16
We have 1s2, 2s2, 2p5.
00:22
And this one will have the same.
00:28
So now we'll only look at how we'll write this out in terms of sigma.
00:33
We're going to try.
00:33
Our ss are going to make up sigmas.
00:41
Our p, we have sigma and pi.
00:50
So here, your 1s will have signal 1s that's filled, as well as sigma star 1s.
01:01
We're going to fill up our sigma 2s and our sigma star 2s, then our sigma 2p...