00:01
In this question, let's assume there is a swing and a bullet with a velocity v and the mass of the bullet is let's say small m and the mass of the swing is capital m.
00:25
Now let's assume this bullet travels with a speed v and gets embedded into this swing.
00:34
Swing and as a result the swing or the pendulum swings to this particular height and here it also comes at rest momentarily rest now let's one by one solve the question of question four has been asked here that what is the combined kinetic energy of the bullet and the block before collision.
01:12
Now we know that before collision the block is at rest.
01:19
So its kinetic energy will be 0 and the kinetic energy of the bullet will be half mb square.
01:26
So k .e1 equals to half mb square.
01:35
Now question number 5 here it has been asked.
01:40
The potential energy of the block with the embedded bullet right after collision.
01:46
Now right after the collision, if you see the block will be at this particular instant only, that is let's say state one only and this let's say a state two.
02:08
So, the potential of the energy of the block with the embedded bullet right after the collision will be equals to 0.
02:27
Now question number 6, what is the pe2 equals to 0? now question number 6, what is the kinetic energy k -e3 of the block with the embedded bullet at maximum height? now at maximum height the block will come at rest.
02:52
So the kinetic energy of the block with the embedded bullet will be so k -e -3 will be equals to 0 as we can see that at a state 2 the block of mass m comes at momentarily rests so the kinetic energy of the block with the embedded bullet at that particular height or maximum height will be zero.
03:28
Now let's look after question number 7...