Question

Consider a 1-D diatomic chain of atoms with masses M1 and M2 connected with the same springs type of spring constant K. The dispersion relation of this model reveals an acoustic and an optical frequency branches. If M1 = 2 M, M2 = M, and ??_0 = ?(K/M), then the frequency band gap between the acoustic and optical branches is (?2-1)?_0 (?3 ) ?_0 (?2 ) ?_0 ?_0

          Consider a 1-D diatomic chain of atoms with masses M1 and M2 connected with the same springs type of spring constant K. The dispersion relation of this model reveals an acoustic and an optical frequency branches. If M1 = 2 M, M2 = M, and ??_0 = ?(K/M), then the frequency band gap between the acoustic and optical branches is

(?2-1)?_0
(?3 ) ?_0
(?2 ) ?_0
?_0

Consider a 1-D diatomic chain of atoms with masses M1 and M2 connected with the same springs type of spring constant K. The dispersion relation of this model reveals an acoustic and an optical frequency branches. If M1 = 2 M, M2 = M, and ??0 = ?(K/M), then the frequency band gap between the acoustic and optical branches is

(?2-1)?0
(?3 ) ?0
(?2 ) ?0
?0

Added by Lisa F.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Suman K

06/28/2022

Step 1

Step 1: Given that M1 = 2M and M2 = M, we can calculate the reduced mass for the system: \[ \mu = \frac{M1 * M2}{M1 + M2} = \frac{2M * M}{2M + M} = \frac{2M^2}{3M} = \frac{2}{3}M \] Show more…

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Consider a 1-D diatomic chain of atoms with masses M1 and M2 connected with the same type of springs with a spring constant K. The dispersion relation of this model reveals an acoustic and an optical frequency branch. If M1 = 2M, M2 = M, and w_0 = V(K/M), then the frequency band gap between the acoustic and optical branches is