00:01
We have been given the length which is 10 meter width 0 .05 meter and the height as 0 .025 meter.
00:16
Inlet flow temperature t1 is equals to 20 degree celsius and the outlet flow temperature t2 is 80 degree celsius.
00:26
Then we have the mass flow rate m which is equals to 0 .01 kilogram per second.
00:35
Now let us calculate the average temperature.
00:37
So the average temperature will be t1 plus t2 by 2 and it will be equals to 50 degree celsius.
00:47
The hydraulic diameter the hydraulic diameter of the rectangular tube can be calculated using the formula 4ac over p where ac is the area so it is a into b and p is the parameter so 2 a plus.
01:04
Now when we substitute the values here we get we get the diameter as 0 .0333 meter.
01:15
Now then we can calculate the average velocity.
01:21
Average velocity will be mass over p a c.
01:27
When we substitute the values and calculate it then we will have the average velocity as 8 .096 into 10 to the power minus 3 meter per second.
01:42
Now we know that the density of water the density of water is 988 .1 kilogram per meter cube and the specific heat is equals to 4181 joule per kg kelvin and the kinematic viscosity u is equals to 0 .547 into 10 to the power minus 3 kilogram by meter second and prandtl number it is equals to 3 .55.
02:28
So these are the some of the known values.
02:30
Now let us calculate the reynolds number.
02:32
So reynolds number is rho v average dh over u.
02:41
When we substitute the values the reynolds number comes out as 487 .02...