Question

Consider a byte-addressable main memory consisting of 16 blocks and a direct-mapped cache with 4 blocks (numbered 0 - 3), where each block has 4 bytes, then which cache block may the address 101010 be mapped to? Group of answer choices block 3 block 1 block 0 block 2

Name: consider a byte addressable main memory consisting of 16 blocks and a direct mapped cache with 4 blocks numbered 0 3 where each block has 4 bytes then which cache block may the address 10101 87344
Uploaded: 2023-03-27T19:54:32-08:00
Duration: 1 min 26 s
Channel: Vysakh M
Description: consider a byte addressable main memory consisting of 16 blocks and a direct mapped cache with 4 blocks numbered 0 3 where each block has 4 bytes then which cache block may the address 10101 87344

          Consider a byte-addressable main memory consisting of 16 blocks and a direct-mapped cache with 4 blocks (numbered 0 - 3), where each block has 4 bytes, then which cache block may the address 101010 be mapped to?
Group of answer choices
block 3
block 1
block 0
block 2

Added by Wesley R.

Computer Science and Information Technology

Trishna Knowledge Systems 2018 Edition

Instant Answer

Solved by Expert Vysakh M

03/27/2023

Step 1

Step 1: Calculate the block size: Since each block has 4 bytes, the block size is 4 bytes. Show more…

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Consider a byte-addressable main memory consisting of 16 blocks and a direct-mapped cache with 4 blocks (numbered 0 - 3), where each block has 4 bytes, then which cache block may the address 101010 be mapped to? Group of answer choices block 3 block 1 block 0 block 2