Since B is rolling a number less than 5, B^C is rolling a 5 or 6. There are 2 outcomes in B^C, so the probability is:
P(B^C) = \frac{2}{6} = \frac{1}{3}
c) To find the probability of A or B, we can use the formula:
P(A \cup B) = P(A) + P(B) - P(A \cap
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