00:01
Hello students, in the question, to determine the force in the x direction of a, we need to consider the equilibrium of forces in the horizontal direction.
00:10
Since there is no external force acting on the x direction, the net force in the x direction must be zero.
00:17
Therefore, the force in x direction at a is equal to zero.
00:27
Now, next, to determine the force in the y direction at a, we need to consider the equilibrium of forces in the vertical direction.
00:34
The external force is 25 n is acting downwards and there are two internal forces acting upwards at a.
00:42
One is the force of member ab and another is the force of member ad.
00:46
So, we have the force in y direction at a as force at a equals to force at ab plus force at ad minus external force.
01:14
That is equal to 15 plus 5 minus 25 which is minus 5 n.
01:20
The negative sign shows that this force is acting downwards.
01:23
Then, to determine the force in y direction at b, we need to consider the equilibrium of forces again at this point and we have force at b equals to force at ab plus force at bc minus external force at b which is again 15 plus 5 sorry minus 25 which is equal to 10 n minus 10 n...