Question

12. Consider a material that has a thermal conductivity varying with temperature as k = \beta T^2 and a constant thermal contraction coefficient, \alpha. Derive a relationship for the overall change in length of a rod of initial length L as a function of the temperature difference between the two ends of the rod. Show the result for the special case where the low temperature end is at 0 K. Compare the answer to that for k = constant. 13. Same as Problem 12 except let the thermal conductivity be a linear function of temperature, k = \beta T.

          12. Consider a material that has a thermal conductivity varying with temperature as
k = \beta T^2 and a constant thermal contraction coefficient, \alpha. Derive a relationship
for the overall change in length of a rod of initial length L as a function of
the temperature difference between the two ends of the rod. Show the result
for the special case where the low temperature end is at 0 K. Compare the
answer to that for k = constant.
13. Same as Problem 12 except let the thermal conductivity be a linear function of
temperature, k = \beta T.
        
Show more…
12. Consider a material that has a thermal conductivity varying with temperature as
k = βT^2 and a constant thermal contraction coefficient, α. Derive a relationship
for the overall change in length of a rod of initial length L as a function of
the temperature difference between the two ends of the rod. Show the result
for the special case where the low temperature end is at 0 K. Compare the
answer to that for k = constant.
13. Same as Problem 12 except let the thermal conductivity be a linear function of
temperature, k = βT.

Added by Lidia R.

Close

University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
AceChat toggle button
Close icon
Ace pointing down

Please give Ace some feedback

Your feedback will help us improve your experience

Thumb up icon Thumb down icon
Thanks for your feedback!
Profile picture
Consider a material that has a linear thermal conductivity as a function of temperature, k=eta T and a constant thermal contraction coefficient, alpha . Derive a relationship for the overall change in length of a rod of initial length L as a function of the temperature difference between the two ends of the rod. Show the result for the special case where the low temperature end is at 0K. Compare the answer to that for k= constant. 12. Consider a material that has a thermal conductivity varying with temperature as k = T2 and a constant thermal contraction coefficient, . Derive a relationship for the overall change in length of a rod of initial length L as a function of the temperature difference between the two ends of the rod. Show the result for the special case where the low temperature end is at 0 K. Compare the answer to that for k =- constant. 13. Same as Problem 12 except let the thermal conductivity be a linear function of temperature, k = T.
Close icon
Play audio
Feedback
Powered by NumerAI
Jennifer Stoner Kathleen Carty
David Collins verified

Jerrah Biggerstaff and 66 other subject Physics 101 Mechanics educators are ready to help you.

Ask a new question

*

Labs

-

Want to see this concept in action?

NEW

Explore this concept interactively to see how it behaves as you change inputs.

View Labs

*

Key Concepts

-
Key Concept
Premium Feature
Explore the core concept behind this problem.
Play button
Key Concept
Premium Feature
Explore the core concept behind this problem.
Your browser does not support the video tag.

*

Recommended Videos

-
consider-a-uniform-rod-of-material-whose-temperature-varies-only-along-its-length-in-the-x-direction

Consider a uniform rod of material whose temperature varies only along its length, in the $x$ direction. By considering the heat flowing from both directions into a small segment of length $\Delta x,$ derive the heat equation, $$ \frac{\partial T}{\partial t}=K \frac{\partial^{2} T}{\partial x^{2}} $$ where $K=k_{t} / c \rho, c$ is the specific heat of the material, and $\rho$ is its density. (Assume that the only motion of energy is heat conduction within the rod; no energy enters or leaves along the sides.) Assuming that $K$ is independent of temperature, show that a solution of the heat equation is $$ T(x, t)=T_{0}+\frac{A}{\sqrt{t}} e^{-x^{2} / 4 K t} $$ where $T_{0}$ is a constant background temperature and $A$ is any constant. Sketch (or use a computer to plot) this solution as a function of $x,$ for several values of $t$ Interpret this solution physically, and discuss in some detail how energy spreads through the rod as time passes.

An Introduction to Thermal Physics

Energy in Thermal Physics

Rates of Processes

7-marks-consider-two-long-slender-rods-of-the-same-diameter-but-different-materials-one-end-of-each-rod-is-attached-to-a-base-surface-maintained-at-100cwhile-the-surfaces-of-the-rods-are-exp-48218

Madhur L.

a-rod-of-length-l-laterally-thermally-insulated-of-uniform-cross-sectional-area-a-consists-of-a-ma-2

A rod of length $l$ (laterally thermally insulated) of uniform cross-sectional area $A$ consists of a material whose thermal conductivity varies with temperature as $K=\frac{K_{o}}{a+b T}$, where $K_{0}, a$ and $b$ are constants. $T_{1}$ and $T_{2}\left(<T_{1}\right)$ are the temperature of two ends of rod. Then rate of flow of heat across the rod is (A) $\frac{A K_{0}}{b l}\left(\frac{a+b T_{1}}{a+b T_{2}}\right)$ (B) $\frac{A K_{0}}{b l}\left(\frac{a+b T_{2}}{a+b T_{1}}\right)$ (C) $\frac{A K_{0}}{b l} \ln \left[\frac{a+b T_{1}}{a+b T_{2}}\right]$ (D) $\frac{A K_{0}}{a l} \ln \left[\frac{a+b T_{2}}{a+b T_{1}}\right]$

A Complete Resource Book in Physics for JEE Main


*

Recommended Textbooks

-
University Physics with Modern Physics

University Physics with Modern Physics

Hugh D. Young 14th Edition
achievement 1,095 solutions
Physics: Principles with Applications

Physics: Principles with Applications

Douglas C. Giancoli 7th Edition
achievement 1,309 solutions
Fundamentals of Physics

Fundamentals of Physics

David Halliday, Robert Resnick , Jearl Walker 10th Edition
achievement 1,727 solutions

*

Transcript

-
00:01 So in this problem, we're considering a uniform rod and material whose temperature varies only along its length in the x direction.
00:07 We're assuming that the only motion of energy is heat conduction within the rod, so no energy enters their leage from the side.
00:14 So we have a rod.
00:18 Here's our section.
00:20 This will be delta x, q1, q2, x minus delta x over 2, global midpoint x plus delta x over 2.
00:38 So considering the heat flowing from both directions into a small segment of length delta x, we want to derive this equation.
00:48 So the rate of heat flow into the segment from the left, according to newton's law of heat conduction, would be t1 over delta t, negative k -a -d -t over tx, where a is the cross -sectional area of the rod, and the heat flow into the section from the right.
01:23 So the total rate of heat flow into the segment.
01:49 We're simplifying that down gives us k a delta x d2t over dx squared.
01:59 So we want to rewrite the above equation in terms of heat capacity, so that would be q is equal to mc delta t and the density of the rod, which is m over a delta x.
02:14 So we'll give us mc delta t over delta t is mk over row.
02:28 Then we want to take the limit of delta t going to zero, and that will just give us k.
02:50 That's for part a.
02:53 And now for part b, we want to assume that k is independent of temperature and verify by substitution that the solution to the heat equation is valid.
03:02 So for this, we just want to evaluate the derivatives...
Need help? Use Ace
Ace is your personal tutor. It breaks down any question with clear steps so you can learn.
Start Using Ace
Ace is your personal tutor for learning
Step-by-step explanations
Instant summaries
Summarize YouTube videos
Understand textbook images or PDFs
Study tools like quizzes and flashcards
Listen to your notes as a podcast
Continue solving this problem
Create a free account to:
  • View full step-by-step solution
  • Ask follow-up questions with Ace AI
  • Save progress and study later
Continue Free
Numerade

Get step-by-step video solution
from top educators

Continue with Clever
or



By creating an account, you agree to the Terms of Service and Privacy Policy
Already have an account? Log In

A free answer
just for you

Watch the video solution with this free unlock.

Numerade

Log in to watch this video
...and 100,000,000 more!


EMAIL

PASSWORD

OR
Continue with Clever