00:01
So in this problem, we're considering a uniform rod and material whose temperature varies only along its length in the x direction.
00:07
We're assuming that the only motion of energy is heat conduction within the rod, so no energy enters their leage from the side.
00:14
So we have a rod.
00:18
Here's our section.
00:20
This will be delta x, q1, q2, x minus delta x over 2, global midpoint x plus delta x over 2.
00:38
So considering the heat flowing from both directions into a small segment of length delta x, we want to derive this equation.
00:48
So the rate of heat flow into the segment from the left, according to newton's law of heat conduction, would be t1 over delta t, negative k -a -d -t over tx, where a is the cross -sectional area of the rod, and the heat flow into the section from the right.
01:23
So the total rate of heat flow into the segment.
01:49
We're simplifying that down gives us k a delta x d2t over dx squared.
01:59
So we want to rewrite the above equation in terms of heat capacity, so that would be q is equal to mc delta t and the density of the rod, which is m over a delta x.
02:14
So we'll give us mc delta t over delta t is mk over row.
02:28
Then we want to take the limit of delta t going to zero, and that will just give us k.
02:50
That's for part a.
02:53
And now for part b, we want to assume that k is independent of temperature and verify by substitution that the solution to the heat equation is valid.
03:02
So for this, we just want to evaluate the derivatives...