00:01
Hello students, according to the question here we have a given differential equation that is x double dot plus 2 gamma multiplied by x dot plus omega naught whole square x is equal to f naught.
00:13
Now, here we have a condition for t that is 0 less than t less than t 1.
00:19
Now, let the solution of be the sum of the steady state solution and a particular integral.
00:23
So, let us suppose that solution be sum of steady state solution steady state solution and particular integral and or we can say particular this is particular integral.
00:49
Now, here we can write x is equal to x that is a steady state solution plus of particular integral that is x p.
00:55
So, here we have to find the sum of a steady state solution.
00:58
So, for steady state steady state let us suppose here that is x double dot plus 2 gamma multiplied by x dot plus omega naught square x is equal to 0.
01:14
So, let x is equal to e to the power that is alpha p.
01:20
Now, in place of this we can write it as that is alpha square plus 2 gamma multiplied by alpha plus omega naught multiplied by that is 4 multiplied by e to the power alpha p it is equal to 0.
01:35
Now, solving here for this we can see this is quadratic equation by using the quadratic formula as.
01:40
So, we got the value of alpha.
01:42
So, we this can be written as that is alpha is equal to minus b.
01:44
So, here we have minus 2 alpha.
01:46
So, we can write minus 2 gamma that is plus of minus 2 to the power b square that is 2 gamma square.
01:52
So, we have 2 gamma full square minus of 4 a c.
01:56
So, we minus of 4 multiplied by 1 multiplied by omega naught square.
02:00
Now, this is whole divided by 2 a.
02:02
So, we have 2 multiplied by 1 that is 2.
02:03
Now, solving for alpha we got the root as minus gamma plus of minus root over that is gamma square minus of omega square...