Consider a plane surface in a uniform electric field as in Figure, where d=15.0cm and ?=70.0o. If the net flux through the surface is 6.00N ? m2/C, find the magnitude of the electric field.
Added by Yash G.
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The electric flux through a surface is given by the equation Φ = E * A * cos(θ), where E is the electric field, A is the area of the surface, and θ is the angle between the electric field and the normal to the surface. Show more…
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Consider a plane surface in a uniform electric field as in Figure P 24.45, where $d=15.0 \mathrm{cm}$ and $\theta=70.0^{\circ} .$ If the net flux through the surface is $6.00 \mathrm{N} \cdot \mathrm{m}^{2} / \mathrm{C},$ find the magnitude of the electric field.
A uniform electric field of magnitude $E=435 \mathrm{N} / \mathrm{C}$ makes an angle of $\theta=65.0^{\circ}$ with a plane surface of area $A=3.50 \mathrm{m}^{2} \mathrm{as}$ in Figure $\mathrm{P} 15.44$ . Find the electric flux through this surface.
Find the electric flux through the plane surface shown in Figure $\mathrm{P} 23.37$ if $\theta=60.0^{\circ}, E=350 \mathrm{~N} / \mathrm{C},$ and $d=5.00 \mathrm{~cm}$. The electric field is uniform over the entire area of the $\operatorname{surface}$.
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