00:01
Hey there, welcome to numerate.
00:02
So we have a variable x that is normally distributed, and we're actually found a probability that x is less than negative 0 .9.
00:11
So let's write the probability where p of x is less than negative 0 .9.
00:24
So since we know this variable is normally distributed, we can safely assume the population mean, which is denoted as mu, equals 0 and population standard deviation denoted as sigma equals 1.
00:43
So with those two terms defined here, we can use our z score equation to find our probability.
00:56
So z equals our x value, which is negative 0 .9, minus our mean, which is 0, and divided by our standard deviation here, which is 1.
01:12
All right.
01:22
So with this, we will still get a value of negative 0 .9, which is our z score value...