Consider a random variable X with a normal distribution whose standard deviation σ is known. The interval x̄ ± 0.84(σ/√n), based on a simple random sample, is to be used to estimate the mean of X. What level of confidence will the interval have?
Added by Andrew B.
Step 1
The interval given is x̅ + 0.84(σ/sqrt(n)). This means that we are estimating the population mean (μ) using the sample mean (x̅) plus a margin of error of 0.84 times the standard error of the mean (σ/sqrt(n)). Show more…
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