00:01
Hello students, in this question we have to find out the cell potential at the given concentration of ions.
00:07
The reduction potential of mercury 2 positive is equal to 0 .851 volts and the reduction potential for chromium 3 positive is equal to minus 0 .714 volts.
00:26
As the reduction potential of mercury is higher, it would be reduced and chromium would be oxidized.
00:35
The standard reduction potential of the cell is equal to the reduction potential of cathode minus the reduction potential of anode.
00:48
The reduction potential for cathode is 0 .851 volts and for anode it is minus 0 .714 volts.
01:01
The standard reduction potential of the cell comes out to be 1 .524 volts.
01:07
According to nernst equation, the reduction potential of the cell is equal to the standard reduction potential of the cell minus 0 .059 divided by n where n is the number of electrons involved multiplied by the log of concentration of species being oxidized divided by the concentration of species being reduced.
01:33
The reduction potential at standard conditions is 1 .524 volts.
01:43
The number of electrons involved in this reaction are 6...