00:01
Hello students, here for the first question it is given that the voltage is equal to 12 volt, capacitance is 5 microfarad and the resistance is equal to 8 into 10 power 5 ohms.
00:15
And for the first part of the question that is a, we have to calculate the time constant.
00:23
So time constant, constant.
00:28
So this is represented by tau and tau is equal to the product of resistance and capacitance that is rc.
00:37
Therefore here resistance is 8 into 10 power 5, capacitance is 5 microfarad, 5 into 10 power minus 6 and we get 40 into 10 power minus 1 and as a result we get the time constant tau is equal to 4 seconds.
01:01
And for the second part we have to calculate the maximum charge on the capacitor, maximum charge.
01:09
So maximum charge occurs when the capacitor is fully charged.
01:15
So therefore q max is equal to e into c.
01:20
E is the potential difference and c is the capacitance.
01:26
So therefore here the potential difference is 12 and c is 5 into 10 power minus 6 and therefore we get 60 into 10 power minus 6 or we can write it as q max equal to 60 micro coulomb.
01:56
Next is we have to calculate the maximum current in the circuit...