00:01
All right, so consider a simple cubic structure with lattice constant of a equals 4 .65a.
00:06
Determine the surface density of atoms in the 100 plane, 110 plane, and 111 plane.
00:12
Show your work.
00:14
All right, so to start off, we'll figure out the planar density of 110 in simple cubic, and that will equal 1 4x times 4 over the square root of 2 times a times a.
00:26
And to simplify more, we'll get 1 over square root.
00:30
Of 2, a squared.
00:32
So the planar density of 110 will be 3 .4 times 10 to the 18 atoms per meter square.
00:39
And that was just by adding the 4 .56, replacing that with a in this equation, like it was given to us.
00:47
So now the planer surface density of 100 plane equals the number of atoms in a plane over the area of the plane.
00:56
So we'll take 1 4 times 4 over a squared...