Consider a situation in which
211 g of P4 are exposed to
240 g of O2.
P4 + 5O2 → 2P2O5
The maximum number of moles of P2O5 that can theoretically
be made from 211 g of P4 and excess oxygen is
3.4 mol.
The maximum number of moles of P2O5 that can theoretically
be made from 240 g of O2 and excess phosphorus is
3 mol.
Question: What is the percent yield if the actual yield
from this reaction is 341 g?
Express your answer to three significant figures and
include the appropriate units.