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Hello students.
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In the question we are given three systems of masses on x -axis and their respective location and we have to calculate the total gravitational potential energy of the system.
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So we use the formula for gravitational potential energy.
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The gravitational potential energy is given by the formula u is equal to minus g m1m2 upon r12.
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Where g is gravitational constant, m1 is the mass of first object, m2 is the mass of other object, and r12 is the distance between them.
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Now, first of all, for m1 and m2, we calculate the value of u12 is equal to minus 6 .67 into 10 to the power minus 11, mass m1, is given as 1 .50 into mass second is 2 .00 upon r12 the distance between the two objects that is 2 .30 minus 1 .50 when we solve it we get the value of u12 as minus 1 .1 .1 into 10 to the power minus 9 june now second for m1 and m3 for m1 and m3 u13 is again minus 6 .67 into 10 to the power minus 11 into mass of first is 1 .50 and the mass of third one is 3 .20 and r13 that is equals to 2 .70 minus 2 .70 minus 2.
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When we solve it we get u13 equals to minus 2 point sorry minus 3 .56 into 10 to the power minus 9 jule.
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Now next we calculate for m2 and m3 for m 2 and m 3 .3 we get u 2 3 we get u 2 3 equals to minus 6 .67 into 10 to the power minus 11, m2, that is 2 .0 into m3, that is 3 .20 upon 2 .70 minus 2 .30, we get the value of u23 equals to minus 2 .2 .2 into 10 to minus 2 .2 .0...