Consider a system with Poisson arrivals with a mean equal to 1 customer per minutes and two identical servers with exponential service times equal to 1 minute. The servers can be arranged into two possible arrangements. ā¢ Arrivals form a single queue to receive service from the first available server. ā¢ The two servers combine to form a single server with a resulting service time that is exponential with a rate equal to 2 customers per minute. Obtain the average number of customers in the system and the average time spent by a customer in the system for each arrangement. Which arrangement will you recommend? Explain.
Added by Mason R.
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The utilization factor of the system is Ļ = Ī»/Ī¼ = 1/2, which is less than 1, so the system is stable. Using Little's law, we can obtain the average number of customers in the system as L = Ī»W, where W is the average time spent by a customer in the system. The Show moreā¦
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