00:01
Here everyone is questioning the first part here a two server queuing system exists in which service times are independent and the mean time is 10 minutes.
00:09
Since the queuing system is considered to be continuous, the waiting time of the consumer is distributed exponentially within a mean time of 5 minutes.
00:18
Okay.
00:19
So in the a part we have here two server queuing system exist in which service times are independent.
00:30
Are independent and the mean time is 10 minutes the mean time is 10 minutes since the queuing system is considered to be continuous the queuing system is considered to be continuous okay since we have in the question that since the queuing system is considered to be continuous is considered to be the waiting time of the customer is distributed exponentially with a mean time of 5 minutes.
01:08
The waiting time of the customer is distributed exponentially with a mean time of 5 minutes.
01:22
With a mean time of 5 minutes.
01:29
So this is the answer of first part.
01:31
Now in the b part we have to calculate the expectation.
01:34
So the formula to calculate the waiting time of the consumers in the system by using the following formula.
01:40
That is w is equal to wq plus t s...