Consider an Aluminum-iron galvanic cell consisting of an Aluminum electrode in a solution of 1 M AlCl3 and an iron electrode in a solution of 1 M FeSO4. Each electrode and its electrolyte are separated by a porous wall, and the whole cell is at 25C. Both electrodes are connected with a copper wire. Below are relevant Eo values. Fe = Fe2+ + 2e -0.440 Cr = Cr3+ + 3e -0.744 Zn = Zn2+ + 2e -0.763 Al = Al3+ + 3e -1.662 (a) Which electrode is the anode? (b) Which electrode does not corrode? (c) In which direction will the electrons flow? (d) What is the delta potential for this galvanic couple (Recall that Delta potential = Ecathode - Eanode)
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The electrode with the lower Eo value is the anode. ** Show more…
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