7. Consider an audio signal with spectral components limited to the frequency band of 300 to 3500 Hz. A PCM signal is generated with a sampling rate of 8000 samples/s. The required output signal-to-quantizing-noise ratio is 40 dB. a. What is the minimum number of uniform quantizing levels needed, and what is the minimum number of bits per sample needed? (2 ?????) b. Calculate the minimum system bandwidth for NRZ modulation required. (2 ?????) c. Repeat pars a) and b) when a A law compander is used with A=50 and 100 (6 ?????) Hint: SQNR = 1.76 + 6.02m SQNR = 4.77 + 6.02m - 20log10 [ln(1 + ?)] SQNR = 4.77 + 6.02m - 20log10 [1 + ln(A)]
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- Given SQNR = 40 dB. - Use the formula: SQNR = 1.76 + 6.02m. - Solve for m: 40 = 1.76 + 6.02m. - 38.24 = 6.02m. - m ≈ 6.35. Show more…
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Consider an audio signal with spectral components limited to the frequency band 300 to 3300 Hz. Assume that a sampling rate of 8000 samples/s will be used to generate a PCM signal. Assume that the ratio of peak signal power to average quantization noise power at the output needs to be 30 dB. What is the minimum number of uniform quantization levels needed, and what is the minimum number of bits per sample needed?
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