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Consider an incompressible flow, boundary layer growing along the surface flat plate with chord of length C. Assuming velocity profile through the boundary layer is given by: $u = v_{\infty} \left(\frac{y}{\delta}\right)^{1/2}$ For $0 < Y < \delta$ And $u = v_{\infty}$ for $y > \delta$ Where $\delta$ is the thickness of boundary layer. Calculate the coefficient of skin friction and comparing with the Blasius solution.

          Consider an incompressible flow, boundary layer growing along the surface flat plate with chord of length C. Assuming velocity profile through the boundary layer is given by:
$u = v_{\infty} \left(\frac{y}{\delta}\right)^{1/2}$ For $0 < Y < \delta$
And $u = v_{\infty}$ for $y > \delta$
Where $\delta$ is the thickness of boundary layer.
Calculate the coefficient of skin friction and comparing with the Blasius solution.
        
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Consider an incompressible flow, boundary layer growing along the surface flat plate with chord of length C. Assuming velocity profile through the boundary layer is given by:
u = v∞((y)/(δ))^1/2 For 0 < Y < δ
And u = v∞ for y > δ
Where δ is the thickness of boundary layer.
Calculate the coefficient of skin friction and comparing with the Blasius solution.

Added by Jasmine H.

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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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Consider an incompressible flow, boundary layer growing along the surface of a flat plate with a chord length of C. Assuming the velocity profile through the boundary layer is given by: u = vo for 0 < y < S and u = Vo for y > S where S is the thickness of the boundary layer. Calculate the coefficient of skin friction and compare it with the Blasius solution.
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Transcript

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00:01 In this question you have to find the point at which u equals 0 .95 capital u and slope of steam line divided by the x and the expression for the skin coefficient and the total drag and momentum thickness.
00:22 So first from the basic equation of lazier's solution we can find that if that equals u.
00:32 U is 0 .9130 at eta equals 3 .5 and fd that will be 0 .95 and eta equals 0 .95 at eta equals 4 so if we want if that equals 0 .95 and have that will be 3 .5 plus 4 4 minus 3 .5 divided by 0 .955 minus 0 .913 times .95 minus 0 .913, eta.
01:25 And that is 3 .94 for eta...
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