00:01
Consider an ordinary shower where hot water at 60 degree celsius is mixed with cold water at 10 degree celsius.
00:11
If it is desired that a steady stream of warm water at 45 degree celsius will be applied, determine the ratio of the mass flow rate of the hot to cold water.
00:27
Assume the heat losses from the mixing chamber to negligible and the mixing to take at a pressure 150 kilo pascal.
00:42
So here we will use the conservation of energy from the law of conservation of energy.
01:04
Energy right so it would be heat lost by hot water equals to heat gained by cold water right.
01:34
So now here therefore you can say mh cp you can say hot water hot water mass is there right.
01:47
So th minus tf final temperature right the temperature of hot water minus final temperature.
01:58
So now here mc that is for cold water cold water mass mc cp basically the formula is mc del t right simply.
02:10
So now here tf would be the common temperature then it will be the temperature of the cold water.
02:20
Now what we will do is cp cp cancels out each other here okay.
02:28
So this becomes equals to mh...