00:01
So friends, let us have a look on this question.
00:01
So, we have given the mass m and the coefficient of static friction between the block and the table is 0 .4.
00:07
This is the mu is equal to 0 .4 we have given here.
00:11
The block is connected to another 2 kg block string that goes through the pulley hanging battery as shown as you can see here, 2 kg block is hanging here.
00:19
Find the minimum value of m such that the system is at rest.
00:24
Means we have to find the minimum value of this capital m so that it can remain on the stationary.
00:34
Moving on this, the tension is t here and t has a value of 2 g.
00:40
This is the tension.
00:41
If this tension is balanced by this friction, we can say it will be at rest.
00:50
So moving on the value of f, it is equal to mu m and what is the value of n is equal to? capital m g because this is the n and this is the value of m g.
01:01
So n is equal to we can say...
