Consider a large truck carrying a heavy load, such as steel beams. A significant hazard for the driver is that the load may slide forward, crushing the cab, if the truck stops suddenly in an accident or even in braking. Assume, for example, that a 11,000 kg load sits on the flat bed of a 20,000 kg truck moving at 14.0 m/s. Assume that the load is not tied down to the truck, but has a coefficient of friction of 0.525 with the flat bed of the truck. (a) Calculate the minimum stopping distance for the truck for which the load will not slide forward relative to the truck. m (b) Is any piece of data unnecessary for the solution? (Select all that apply.) speed of truck coefficient of friction mass of truck mass of load
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Given: Mass of load (m) = 11,000 kg Coefficient of friction (μ) = 0.525 Acceleration due to gravity (g) = 9.8 m/s^2 Calculate the weight of the load: Weight = mass x gravity Weight = 11,000 kg x 9.8 m/s^2 Weight = 107,800 N Calculate the maximum frictional Show more…
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Consider a large truck carrying a heavy load, such as steel beams. A significant hazard for the driver is that the load may slide forward, crushing the cab, if the truck stops suddenly in an accident or even in braking. Assume, for example, that a 9000 kg load is located on the flatbed of a 25000 kg truck moving at 15.0 m/s. Assume the load is not tied down to the truck and assume that the coefficient of friction between the load and the truck bed is 0.600. (a) Calculate the minimum stopping distance for the truck for which the load will not slide forward relative to the truck. ______m (b) Is any piece of data unnecessary for the solution? (Select all that apply.) (Below) - speed of truck - mass of load - coefficient of friction - mass of truck
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Consider a large truck carrying a heavy load, such as steel beams. A significant hazard for the driver is that the load may slide forward, crushing the cab, if the truck stops suddenly in an accident or even in braking. Assume, for example, that a 11000-kg load sits on the flatbed of a 20000-kg truck moving at 14.0 m/s. Assume the load is not tied down to the truck and has a coefficient of static friction of 0.500 with the truck bed. (a) Calculate the minimum stopping distance for which the load will not slide forward relative to the truck. m(b) Is any piece of data unnecessary for the solution? (Select all that apply.) mass of the load mass of the truck velocity coefficient of static friction all are necessary
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A flatbed truck is loaded with a stack of sacks of cement whose combined mass is $1143.5 \mathrm{~kg}$. The coefficient of static friction between the bed of the truck and the bottom sack in the stack is $0.372,$ and the sacks are not tied down but held in place by the force of friction between the bed and the bottom sack. The truck accelerates uniformly from rest to $56.6 \mathrm{mph}$ in $22.9 \mathrm{~s}$. The stack of sacks is $1 \mathrm{~m}$ from the end of the truck bed. Does the stack slide on the truck bed? The coefficient of kinetic friction between the bottom sack and the truck bed is $0.257 .$ What is the work done on the stack by the force of friction between the stack and the bed of the truck?
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