00:01
A pi mazon of rest mass m pi decaying at rest into a muon of m new and a neutrino of negligible or zero rest mass.
00:16
So we want to prove that the kinetic energy of the muon is equal to m pi minus m new square times c squared over two m pi.
00:34
The first thing we're going to note is that because the neutrino has no rest mass, we can find its energy using the following equation.
00:44
You have ev is equal to p of the v squared, c squared, plus mv squared, c the fourth to the one -half power.
00:59
And this will simplify to pvc.
01:02
Now, since this neutrino decayed at rest, both the neutrino, both the pi mazon, sorry, since the pi maizon decayed at rest, the muon and neutrino are going to have equal and opposite momentum.
01:25
So we have p new is equal to pv, and we're just going to call that p for the rest of this problem.
01:32
So we have the energy of the pi mazon is equal to the energy of the produced neutrino and the energy of the produced pi mazon.
01:51
And that move on.
01:54
So we have m times pi c squared since the pi mazon is not moving.
02:02
This is only the rest energy that is being set equal to...