00:01
So this question asked for the magnitude of the tension force on the rope and the force that the person must exert on our feet to prevent sliding down and the coefficient of a brick shot.
00:25
So to solve this problem, let us draw first the free body diagram of the system.
00:33
Suppose this is the center of mass of the climber.
00:37
This is her weight.
00:41
Pulling her vertically downwards.
00:46
And this is the tension, an angle of 31 degrees from the vertical.
01:13
So we can say that the vertical component is equals to cosine 31 degrees.
01:23
And for the horizontal component, which pointed at this direction, this is the sine 31 degrees.
01:34
Now, from the figure, the surface of the mountain exerts a force on the leg of the climber in this direction, which is 15 degrees from the horizontal.
02:16
We know that there is a normal force, exis, perpendicular to the surface.
02:23
This normal force is the component of f to horizontal plane.
02:34
Normal force is equals to f cosine degrees.
02:42
Now opposite the weight pulling the climber upwards to prevent her from sleeping is the friction force.
02:57
And since friction force is related to normal force, this friction force is equal to the component of f in vertical plane.
03:06
So this is small f is equals to big f sign 15 degrees.
03:15
So we have here all the forces in the x and y plane.
03:19
Now let's write the net forces.
03:24
So to maintain the libbyum or to maintain stationary not sleeping, their net force would be equals to zero from the first law motion...