Question

Consider the ac equivalent circuit provided. Assume $R_E = 1k\Omega$ and $R_C = 3k\Omega$, and the transistor parameters for both $Q_1$ and $Q_2$ are: $I_{CQ} = 0.5 mA$ $\beta = 100$ $V_A = 100 V$ $V_T = 25 mV$ Determine: $g_m = \boxed{} mS$ $r_{\pi} = \boxed{} k\Omega$ $r_o = \boxed{} k\Omega$ $A_{v1} = V_1/V_i = \boxed{} V/V$ $A_{v2} = V_o/V_1 = \boxed{} V/V$ $A_v = V_o/V_i = \boxed{} V/V$

          Consider the ac equivalent circuit provided. Assume $R_E = 1k\Omega$ and $R_C = 3k\Omega$, and the transistor parameters for both $Q_1$ and $Q_2$ are:
$I_{CQ} = 0.5 mA$
$\beta = 100$
$V_A = 100 V$
$V_T = 25 mV$
Determine:
$g_m = \boxed{} mS$
$r_{\pi} = \boxed{} k\Omega$
$r_o = \boxed{} k\Omega$
$A_{v1} = V_1/V_i = \boxed{} V/V$
$A_{v2} = V_o/V_1 = \boxed{} V/V$
$A_v = V_o/V_i = \boxed{} V/V$

Consider the ac equivalent circuit provided. Assume RE = 1kΩ and RC = 3kΩ, and the transistor parameters for both Q1 and Q2 are:
ICQ = 0.5 mA
β = 100
VA = 100 V
VT = 25 mV
Determine:
gm = mS
rπ = kΩ
ro = kΩ
Av1 = V1/Vi = V/V
Av2 = Vo/V1 = V/V
Av = Vo/Vi = V/V

Added by Rebecca D.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Adi S

07/16/2023

Step 1

Since Rg=1k and Rc=3k, we can use Ohm's law: 9m = Rg*Ico*Rc 9m = 1*0.5*3k 9m = 3.125 kΩ Show more…

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Consider the ac equivalent circuit provided . Assume R E =1k Omega and R C =3k Omega , and the transistor parameters for both Q 1 and Q 2 are : Ico = 0.5 mA beta = 100 V A =100V V T =25 mV Consider the ac equivalent circuit provided.Assume Rg=1k and Rc =3k,and the transistor parameters for both Q and Q are Ico=0.5 mA =100 V=100 V V =25 mV V Determine: 9m = mS f = K ro= k Av1=VN= V/V Ay2 = Vo/V = VN Ay = Vo/V: = VN