00:01
Hi, so to solve for this we need to determine first the limiting reactant, convert the given mass of reactants to moles.
00:08
We'll start with p4.
00:09
If we have 45 .81 grams of this compound, divide the molar mass of p4, that's 123 .88 grams and then we have here moles, so we could cancel this one and this will give us 0 .3698 moles of p4.
00:30
And then for toluene gas, we have 130 .9 grams convert to moles, we have 70 .9 grams and then we have here moles, could cancel this one and this will give us 1 .846 and this is moles of cl2.
00:51
And solving for mole ratio, mole ratio is the number of moles of the reactant divided by the coefficient of that reactant from the balance equation.
01:01
So for p4, we have 0 .3698, coefficient of this compound is 1, this will give us 0 .3698.
01:10
For cl2, we have 1 .846, coefficient of toluene gas is 6 and this will give us 0 .308.
01:18
And whichever gives the smallest mole ratio will be the limiting reactant.
01:22
Therefore, toluene gas is our limiting reactant.
01:27
So to solve for the amount of the excess reactant remaining after the reaction is completed, we have to solve first for the mass of p4 reactant...