00:01
Hi, in this question we are given with the reaction x plus y gives z.
00:05
We are given with concentration of x and y in initial state in experiment 1 and 2 in this manner, along with the initial rate of formation of z for first experiment that is equal to r.
00:19
Here we are asked to calculate the initial rate of formation of z in second experiment.
00:26
It is given in the question that the order of reaction with respect to, to x is first order and order of reaction with respect to y is second order.
00:36
Therefore we can write the rate law expression that will be equal to k, that is the rate constant, into concentration of x to the power 1, into concentration of y to the power.
00:51
To find the initial rate of formation of z, we need to divide the experiment 2 values by experiment 1.
01:01
Let us consider the initial rate of formation of z in experiment 2 is x, and we know that the initial rate of formation of z in experiment 1 is r.
01:13
It is equal to k into concentration of x in experiment 2, that is 0 .20, into concentration of y in experiment 2, that is 0 .20, divided by k...