00:01
Hi, in the given problem there is a combination of resistors which is having a battery providing a potential of 24 volt then a resistor having a value of r1 then three resistors in parallel this is r4 this is r2 and this is r3 all these three are actually in parallel combination then the fifth resistance r5 and that's all of the combination now the values of these resistors are given as r1 r2 for r1 this is 15 .0 oom r2 is equal to r4 and having the value of 40 .0 om and at last r3 is having a value of 10 .0 om.
01:20
A common current will start passing through this combination, the current i coming out of the battery and passing through r1, it will be divided into three parts across this combination i2, i3 and i4, which will again get combined here at this junction, and i current will be passing through resistor r5 also.
01:49
Now, in the first part of the problem, we have to find effective resistance of this combination for which as these three are in parallel.
02:02
So, using the rule for the parallel combination, if the parallel combination is represented as rp, then 1 by rp will be equal to 1 by r2 which is having a value of 40 plus 1 by r 3 which is 20 plus 1 by r 4 which is again 40.
02:27
Lcm 40 so this is 1 plus 2 plus 1.
02:31
So it comes out to be 4 by 40.
02:36
So the parallel combination here is 10 oom.
02:43
Now this r1, rp, and r5 all are in series combination.
02:58
So effective resistance of this combination is r1 plus rp plus r5...