0:00
All right, hello.
00:01
In this question, we have two things we're trying to find.
00:03
We're asked, given this circuit, find the current in the 31 ohm resistor.
00:07
So there's going to be some current going through this that we want to find.
00:11
And we're also asked to find the voltage potential difference between points a and b.
00:16
So in order to do this, i'm going to simplify this circuit down a little bit.
00:21
So if i look at this, these two resistors here meet at this junction here.
00:27
And so from any other component, they're going to just look at one resistor.
00:32
And so they're going to have an equivalent resistance.
00:35
Since they're in parallel, it's going to be 1 over 10 plus 1 over 5 is equal to 1 over the equivalent resistance.
00:44
And then i know that my 5 ohm resistor and my 31 ohm resistor, they're going to have the same current going through them.
00:53
And from outside the circuit, from points a and b, they're going to look like a single resistor with a resistance of 36 ohms.
01:01
So i can go ahead and redraw this circuit a little bit.
01:04
And it'll look like this.
01:06
And now i have something that looks like this.
01:09
Well, if i follow from my positive terminal here and i go out, i'm going to hit this junction here.
01:15
And then the current's going to split that way and this way.
01:19
So i want to just redraw this again.
01:23
Well, so the current's going to go through those two resistors and then meet back up here and go through this resistor.
01:27
So i'm going to redraw this again just to make it a little more easy to understand.
01:34
So i'm going to have my voltage source.
01:36
And then i can either go through a 3 .33 ohm resistor or i can go through that 36 ohm resistor.
01:47
And then regardless, i'm going to meet back up and then go through a 10 ohm resistor before hitting the battery again.
01:55
And so i want to find the current in this 36 ohm resistor.
02:00
And the ab voltage points are going to be on either side of those two resistors.
02:05
So this circuit just looks a lot nicer and easier to understand.
02:10
So that's why i've done this.
02:12
And then in order to solve this even more, if this is 25 .10 volts, i'm going to redraw the circuit even simpler.
02:20
So i have 25 .0 volts here.
02:23
I'm going to go through one resistor and then through a second resistor, and then i'm back.
02:27
This will be my 10 ohm resistor...