Question

Consider the circuit shown in the figure. A short time after closing the switch, the charge on the capacitor is 60.0% of its initial charge. Assume the circuit has a time constant of 17.7 s. (a) Calculate the time interval required (in s) for the capacitor to reach this charge. (b) If $R = 200 \text{ k}\Omega$, what is the value of $C$ (in $\mu F$)? Submit Answer

          Consider the circuit shown in the figure. A short time after closing the switch, the charge on the capacitor is 60.0% of its initial charge. Assume the circuit has a time constant of 17.7 s.
(a) Calculate the time interval required (in s) for the capacitor to reach this charge.
(b) If $R = 200 \text{ k}\Omega$, what is the value of $C$ (in $\mu F$)?
Submit Answer

Consider the circuit shown in the figure. A short time after closing the switch, the charge on the capacitor is 60.0% of its initial charge. Assume the circuit has a time constant of 17.7 s.
(a) Calculate the time interval required (in s) for the capacitor to reach this charge.
(b) If R = 200 kΩ, what is the value of C (in μ F)?
Submit Answer

Added by Kathy B.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Penny Riley

10/14/2022

Step 1

Step 1: The time constant (τ) of the circuit can be calculated using the formula τ = R * C, where R is the resistance and C is the capacitance. Show more…

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Consider the circuit shown in the figure. A short time after closing the switch, the charge on the capacitor is 60.0% of its final charge. Assume the circuit is not connected for 7 seconds. a) Calculate the time interval required (in seconds) for the capacitor to reach this charge. b) If R = 200 kΩ, what is the value of C (in microfarads)? [Submit Answer]