00:01
So for this problem, we need to calculate the current through each resistor.
00:08
So for part a, since r2 and r4 are in series, it's pretty clear that i2 equals i4, and we can calculate the effective resistance of r24, which is r2 plus r4, equals 16 .9 oms.
01:02
And r3 are in parallel with r24.
01:09
So we can calculate the effective resistance of r3 -24, which is r3 times r24, divided by r3 plus r24.
01:31
So this is 16 .9 times 7 .1, divide up by 24, which is approximately 5 oms.
01:52
And r1 are in series with r324.
01:58
So we can calculate the total resistance of the system, which is r1 plus r324, equals 18 oms.
02:19
So from the total resistance we can calculate i1.
02:26
So i1 equals i equals emf divided by the total resistance.
02:42
So this equals point a3 ambiars.
02:49
And you need two sick figures, so this is point a.
03:11
And since i2 plus i3 equals i1, and i2 times r24 equals i3 times r3.
03:41
So from this two equations, we can calculate i2 and i3.
03:50
So i2 equals 0 .247, here, which is approximately 0 .2 .2.
04:12
And i3 equals 0 .59.
04:24
You can run it up to 0 .6...