Question

Consider the combustion of liquid octane (molar mass=114.23 g/mol) and the associated enthalpy change. 2C8H18(l)+25O2(g)⟶16CO2(g)+18H2O(g) ΔH=−10860 kJ What mass (in g) of octane needs to be burned to provide 5099.0 kJ of energy? Type answer: Dispense the liquid directly from the reagent bottle whenever it is needed. Insert a pipet into the reagent bottle as many times as needed to get the desired amount of liquid.

Name: consider the combustion of liquid octane molar mass11423 gmol and the associated enthalpy change 2c8h18l25o2g16co2g18h2og h10860 kj what mass in g of octane needs to be burned to provide 509 79762
Uploaded: 2022-06-16T15:21:42-08:00
Duration: 1 min 51 s
Channel: John Incabo
Description: consider the combustion of liquid octane molar mass11423 gmol and the associated enthalpy change 2c8h18l25o2g16co2g18h2og h10860 kj what mass in g of octane needs to be burned to provide 509 79762

          Consider the combustion of liquid octane (molar mass=114.23 g/mol) and the associated enthalpy change.
2C8H18(l)+25O2(g)⟶16CO2(g)+18H2O(g) ΔH=−10860 kJ
What mass (in g) of octane needs to be burned to provide 5099.0 kJ of energy?
Type answer:
Dispense the liquid directly from the reagent bottle whenever it is needed.
Insert a pipet into the reagent bottle as many times as needed to get the desired amount of liquid.

Added by Vanessa P.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert John Incabo

06/16/2022

Step 1

From the balanced equation, we see that the combustion of 2 moles of octane releases -10860 kJ. Therefore, the energy released per mole of octane is: \[ \text{Energy per mole of octane} = \frac{-10860 \text{ kJ}}{2 \text{ moles}} = -5430 \text{ kJ/mole} \] Show more…

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Consider the combustion of liquid octane (molar mass=114.23 g/mol) and the associated enthalpy change. 2C8H18(l)+25O2(g)⟶16CO2(g)+18H2O(g) ΔH=−10860 kJ What mass (in g) of octane needs to be burned to provide 5099.0 kJ of energy? Type answer: Dispense the liquid directly from the reagent bottle whenever it is needed. Insert a pipet into the reagent bottle as many times as needed to get the desired amount of liquid.