(a) At $25^{\circ} \mathrm{C}$, the temperature is $298 \mathrm{K}$. Plugging in the given values, we get:$$\Delta G^{\circ} = (55.3 \times 10^3 \mathrm{J}) - (298 \mathrm{K})(175.7 \mathrm{J}/\mathrm{K})$$Calculating the result, we find:$$\Delta G^{\circ} =
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